A) Rs. 1550
B) Rs. 1650
C) Rs.1750
D) Rs. 2000
Correct Answer: C
Solution :
Let the principal amount be Rs. P. By given condition, \[SI=\frac{1}{2}CI\] \[\Rightarrow \] \[\frac{P\times 8\times 3}{100}=\frac{1}{2}\left[ 4000{{\left( 1+\frac{10}{100} \right)}^{2}}-4000 \right]\] \[\Rightarrow \] \[\frac{24}{100}=\frac{1}{2}\left[ 4000\times \frac{121}{100}-4000 \right]\] \[=\frac{1}{2}[4840-4000]\] \[\Rightarrow \] \[\frac{24P}{100}=420\] \[\Rightarrow \] \[P=\frac{42\times 100}{24}\] \[\Rightarrow \] \[P=Rs.\,1750\]You need to login to perform this action.
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