A) No loss no gain
B) Loss, Rs. 1000
C) Gain, Rs.1000
D) Loss, Rs. 2000
Correct Answer: B
Solution :
Let the cost price of a refrigerator be Rs. x and that of a camera be Rs. y. Since, a refrigerator was sold for Rs. 12000 at a loss of 20%. \[\therefore \] \[12000=x\left( \frac{100-20}{100} \right)\] \[\Rightarrow \] \[x=\frac{12000\times 100}{120}=Rs.15000\] and a camera was sold for Rs. 12000 at a profit of 20%. \[\therefore \] \[12000=y\left( \frac{100+20}{100} \right)\] \[\Rightarrow \] \[y=\frac{12000\times 100}{120}=Rs.10000\] Total cost price of both items \[=x+y\] \[=15000+10000\] and total selling price of both items \[=12000+12000\] \[=Rs.\,24000\] \[\therefore \] Loss \[=25000-24000\] \[=Rs.\,1000\]You need to login to perform this action.
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