A) 24
B) 18
C) 12
D) 6
Correct Answer: C
Solution :
Let the first number \[=3x\] Second number \[=6x\] and third number \[=2x\] According to question, \[44=\frac{3x+6x+2x}{3}\] \[\Rightarrow \] \[x=\frac{44\times 3}{11}=12\] \[\therefore \] First number \[=3\times 12=36\] and third number \[=\text{ }2\times 12=4\] Hence, required difference \[=36-24=12\]You need to login to perform this action.
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