A) 0
B) 1
C) 2
D) \[\frac{1}{2}\]
Correct Answer: C
Solution :
\[{{\left[ {{64}^{\frac{2}{3}}}\times {{2}^{-2}}\div {{8}^{0}} \right]}^{\frac{1}{2}}}\] \[={{\left[ {{4}^{2}}\times \frac{1}{{{2}^{2}}} \right]}^{\frac{1}{2}}}\] \[={{\left[ 16\times \frac{1}{4} \right]}^{\frac{1}{2}}}\] \[={{[4]}^{\frac{1}{2}}}=2\]You need to login to perform this action.
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