A) 3 km
B) 4 km
C) 5 km
D) 6 km
Correct Answer: C
Solution :
The movements of the man are as shown in figure (A to B, B to C, C to D, D to E). Clearly, \[DF=BC=5\text{ }km.\] \[EF=(DE-DF)=(9-5)\,km=4\,km.~~~\] \[BF=CD=2\,km.\] \[AF=AB+BF=AB+CD~\] \[BF=CD=2km.\] \[=(1+2)\,km=3\,km\] \[\therefore \] Man's distance from starting point A \[=AE=\sqrt{A{{F}^{2}}+E{{F}^{2}}}\] \[=\sqrt{{{3}^{2}}+{{4}^{2}}}=\sqrt{25}=5\,km.\]You need to login to perform this action.
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