A) 56.25
B) 50
C) 12.5
D) 156.25
Correct Answer: A
Solution :
Let the side of a square \[=a\,\,unit\] \[\therefore \] Area of a square \[={{a}^{2}}\,sq\,unit\] New side of a square = 125% of a \[=\frac{125a}{100}=\frac{5a}{4}\] \[\therefore \] New area of square \[={{\left( \frac{5a}{4} \right)}^{2}}\] \[=\left( \frac{5a}{4} \right)\times \left( \frac{5a}{4} \right)=\frac{25{{a}^{2}}}{16}\] Change in area \[=\frac{25{{a}^{2}}}{16}-{{a}^{2}}=\frac{9{{a}^{2}}}{16}\] Percentage of change \[=\frac{9{{a}^{2}}/16}{{{a}^{2}}}\times 100%=\frac{9\times 100}{16}%\] \[=56.25%\]You need to login to perform this action.
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