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SSC Sample Paper SSC CGL - Sample Paper-24

  • question_answer
    If \[a:b=c:d=e:f=1:2,\] then \[(pa+qc+re):(pb+qd+rf)\] is equal to

    A) \[p:(q+r)\]                     

    B) \[(p+q):r\]

    C) 2 : 3                             

    D) 1 : 2

    Correct Answer: D

    Solution :

    \[\because \] \[a:b=c:d=e:f=1:2\] \[\Rightarrow \]   \[a=\frac{1}{2}b,\] \[c=\frac{1}{2}d,\] \[e=\frac{1}{2}f\] \[\therefore \]      \[\frac{pa+qc+re}{pb+qd+rf}=\frac{\frac{1}{2}pb+\frac{1}{2}qd+\frac{1}{2}rf}{pb+qd+rf}\]             \[=\frac{1}{2}\left( \frac{pb+qd+rf}{pb+qd+rf} \right)=\frac{1}{2}=1:2\]


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