A) \[1+2\sqrt{2}\]
B) \[\sqrt{3}+\sqrt{6}\]
C) \[\sqrt{2}+\sqrt{7}\]
D) \[\sqrt{2}+\sqrt{5}\]
Correct Answer: C
Solution :
\[9+2\sqrt{14}={{(\sqrt{7})}^{2}}+{{(\sqrt{2})}^{2}}+2\sqrt{7}\times \sqrt{2}\] \[={{(\sqrt{7}+\sqrt{2})}^{2}}\] \[\therefore \] \[\sqrt{9+2\sqrt{14}}=(\sqrt{7}+\sqrt{2})\]
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