A) 6
B) 8
C) 10
D) 4
Correct Answer: D
Solution :
Suppose, x number added to each term, they become same proportional. i.e., \[(4+x),\] \[\text{(}10+x\text{)},\] \[\text{(}12+x\text{)},\] \[(24+x)\] are in proportional. \[\therefore \] \[(4+x):(10+x)::(12+x):(24+x)\] \[\Rightarrow \] \[\frac{4+x}{10+x}=\frac{12+x}{24+x}\] \[\Rightarrow \] \[(4+x)(24+x)=(10+x)(12+x)\] \[\Rightarrow \] \[96+28x+{{x}^{2}}=120+22x+{{x}^{2}}\] \[\Rightarrow \] \[6x=24\] \[\Rightarrow \] \[x=4\]
You need to login to perform this action.
You will be redirected in
3 sec
