A) 13 :14
B) 14 :13
C) 10 : 11
D) 1 : 2
Correct Answer: A
Solution :
\[\because \] \[x:y=3:1\] \[\therefore \] \[\frac{{{x}^{3}}-{{y}^{3}}}{{{x}^{3}}+{{y}^{3}}}=\frac{{{\left( \frac{x}{y} \right)}^{3}}-1}{{{\left( \frac{x}{y} \right)}^{3}}+1}=\frac{{{(3)}^{3}}-1}{(3)+1}\] \[=\frac{27-1}{27+1}\] \[=\frac{26}{28}=13:14\]You need to login to perform this action.
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