A) 18
B) 22
C) 25
D) 27
Correct Answer: C
Solution :
Total of 8 numbers \[=8\times 20\] \[=160\] Total of fast 2 numbers \[=\frac{31}{2}\times 2=31\] Total of next 3 numbers \[=\frac{64}{3}\times 3=64\] Let the 8th number be x, then Sixth number will be \[x-7\] and seventh number will \[x-3.\] \[\therefore \] \[31+64+x+x-7+x-3=160\] \[\Rightarrow \] \[3x=160-31-64+10\] \[=75\] \[\Rightarrow \] \[x=25\]\You need to login to perform this action.
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