A) 12000
B) 12100
C) 12200
D) 12400
Correct Answer: B
Solution :
\[\because \] \[{{I}^{3}}+{{2}^{3}}+....+{{10}^{3}}=3025\] Now, \[4+32+108+....+4000\] \[=4[1+8+27+....+1000]\] \[=4[1+{{3}^{3}}+{{3}^{3}}+....+{{10}^{3}}]\] \[=4\times 3025\] \[=12100\]You need to login to perform this action.
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