A) \[p:(q+r)\]
B) \[(p+q):r\]
C) 2 : 3
D) 1 : 2
Correct Answer: D
Solution :
\[\because \] \[a:b=c:d=e:f=1:2\] \[\Rightarrow \] \[a=\frac{1}{2}b,\] \[c=\frac{1}{2}d,\] \[e=\frac{1}{2}f\] \[\therefore \] \[\frac{pa+qc+re}{pb+qd+rf}=\frac{\frac{1}{2}pb+\frac{1}{2}qd+\frac{1}{2}rf}{pb+qd+rf}\] \[=\frac{1}{2}\left( \frac{pb+qd+rf}{pb+qd+rf} \right)=\frac{1}{2}=1:2\]You need to login to perform this action.
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