A) 0.3
B) 2.3
C) 1
D) 2
Correct Answer: D
Solution :
\[\therefore \] \[\frac{{{(2.3)}^{3}}-0.027}{{{(2.3)}^{2}}+0.69+0.09}=\frac{{{(2.3)}^{3}}-{{(0.3)}^{3}}}{{{(2.3)}^{2}}+0.69+0.09}\] \[=\frac{(2.3-0.3)[{{(2.3)}^{2}}+{{(0.3)}^{2}}+2.3\times 0.3]}{{{(2.3)}^{2}}+0.69+0.09}\] \[=\frac{2[{{(2.3)}^{2}}0.09+0.69]}{{{(2.3)}^{2}}+0.69+0.09}=2\]You need to login to perform this action.
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