A) 6%
B) 8%
C) 10%
D) 12%
Correct Answer: B
Solution :
Given, \[CI=Rs.\,832,\text{ }\] \[SI=Rs.\,800,\] \[T=2\,yr\] Since, \[CI=P\left\{ {{\left( 1+\frac{R}{100} \right)}^{T}}-1 \right\}\] \[\therefore \] \[832=P\left\{ {{\left( 1+\frac{R}{100} \right)}^{2}}-1 \right\}\] ?(i) Also, \[CI=\frac{P\times R\times T}{100}\] \[\Rightarrow \] \[800=\frac{P\times R\times 2}{100}\] \[\Rightarrow \] \[P=\frac{40000}{R}\] \[\therefore \] From Eq. (i), \[832=\frac{40000}{R}\left( \frac{{{R}^{2}}}{10000}+\frac{2R}{100} \right)\] \[\Rightarrow \] \[832=4R+800\] \[\Rightarrow \] \[R=\frac{32}{4}=8%\]You need to login to perform this action.
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