A) 40
B) 60
C) 160
D) 280
Correct Answer: D
Solution :
Let the HCF of two numbers \[=x\] LCM of two numbers \[=14x\] By given condition, \[\text{HCF}+\text{LCM}=600\] \[\Rightarrow \] \[x+14x=600\] \[\Rightarrow \] \[x=\frac{600}{15}=40\] \[\therefore \] HCF of two numbers \[=40\] and LCM of two numbers \[=14\times 40=560\] We know that, \[\text{HCF}\times \text{LCM}\] = product of two numbers \[\Rightarrow \] \[40\times 560=80\times \text{second number}\] \[\therefore \] Second number \[=\frac{40\times 560}{80}=280\]You need to login to perform this action.
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