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SSC Sample Paper SSC CGL - Sample Paper-26

  • question_answer
    Two .numbers are in the ratio \[1\frac{1}{2}:2\frac{2}{3}.\] When each of these is increased by 15, they become in the ratio \[1\frac{2}{3}:2\frac{1}{2}.\] The greater of the numbers is                             

    A) 27                                

    B) 36   

    C) 48                    

    D) 64

    Correct Answer: C

    Solution :

    Ratio of number \[=1\frac{1}{2}:2\frac{2}{3}\] \[=\frac{3}{2}:\frac{8}{3}=9:16\] Let the numbers are 9x and 16x According to question,             \[\frac{9x+15}{16x+15}=\frac{5/3}{5/2}\] \[\Rightarrow \]   \[\frac{9x+15}{16x+15}=\frac{2}{3}\] \[\Rightarrow \]   \[27x+45=32x+30\] \[\Rightarrow \]   \[5x=15\] \[\Rightarrow \]   \[x=3\]  \[\therefore \] The greater number \[=16\times 3=48\]         


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