A) \[\frac{7}{3}\]
B) \[\frac{14}{3}\]
C) \[\frac{2}{3}\]
D) \[\frac{1}{3}\]
Correct Answer: B
Solution :
\[LCM\left( \frac{2}{3},\frac{7}{9},\frac{14}{15} \right)=\frac{LCM(2,7,14)}{HCF(3,9,15)}=\frac{14}{3}\]You need to login to perform this action.
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