A) Rs. 200
B) Rs. 220
C) Rs. 240
D) Rs. 260
Correct Answer: A
Solution :
Let cost of 1 table be Rs. x and cost of 1 chair be Rs. y. \[4x+5y=1000\] ?(i) Table chair CP \[4x\] \[5y\] SP \[4x\left( 1+\frac{1}{10} \right)=\frac{44x}{10}5y\left( 1+\frac{1}{5} \right)=6y\] \[\because \] \[\text{SP}-\,\,\text{CP}=\text{Profit}\] \[\therefore \] \[\left( \frac{44x}{10}-4x \right)+6y-(4x+5y)=120\] \[\Rightarrow \] \[\frac{4x}{10}+y=120\] ?(ii) From Eqs. (i) and (ii), we get \[x=Rs.\,200\]You need to login to perform this action.
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