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SSC Sample Paper SSC CGL - Sample Paper-26

  • question_answer
    If a = 0.1039, then the value of \[\sqrt{4{{a}^{2}}-4a+1}+3a\] is

    A) 0.1039             

    B) 0.2078

    C) 1.1039 

    D) 2.1039

    Correct Answer: C

    Solution :

    \[\sqrt{4{{a}^{2}}-4a+1}+3a=\sqrt{{{(2a-)}^{2}}+3a}\] \[=2a-1+3a=a+1\] \[=1+0.1039\]             \[=1.1039\]       


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