A) 44
B) 55
C) 66
D) 77
Correct Answer: B
Solution :
Let two number be x and y, Then \[\frac{x}{y}=\frac{3}{5}\] \[\Rightarrow \] \[5x-3y=0\] and \[\frac{x-9}{y-9}=\frac{12}{23}\] \[\Rightarrow \] \[23x-207=12y-108\] \[\Rightarrow \] \[23x-12y=99\] Multiply Eq. (i) by 4 and subtracting Eq. (ii) from Eq. (i), we et \[3x=99~\] \[\Rightarrow \] \[x=3\] \[\therefore \] From Eq. (i) \[5(33)-3y=0\] \[\Rightarrow \] \[y=5\times 11=55\] \[\therefore \] The second number (y) \[=55\]You need to login to perform this action.
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