A) \[1:\sqrt{2}\]
B) \[\sqrt{2}:1\]
C) 1 : 2
D) 2 : 1
Correct Answer: B
Solution :
Slant height of the cone \[=\sqrt{{{r}^{2}}+{{r}^{2}}}\] \[=\sqrt{2}r\] \[\therefore \] Ratio of their curves surface are \[2\pi {{r}^{2}}:\pi r\times \sqrt{2r}\] \[2\pi {{r}^{2}}:\sqrt{2}\pi {{r}^{2}}=\sqrt{2}:1\]You need to login to perform this action.
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