A) 1
B) \[{{(2)}^{\frac{1}{4}}}\]
C) \[{{(3)}^{\frac{1}{3}}}\]
D) \[{{(4)}^{\frac{1}{4}}}\]
Correct Answer: B
Solution :
Let number be x, then its reciprocal be\[\frac{1}{y}\] By given condition, \[{{x}^{2}}+\frac{1}{{{x}^{2}}}=3\left( {{x}^{2}}-\frac{1}{{{x}^{2}}} \right)\] \[\therefore \] \[{{x}^{2}}+\frac{1}{{{x}^{2}}}=3{{x}^{2}}-\frac{3}{{{x}^{2}}}\] \[\Rightarrow \] \[2{{x}^{2}}=\frac{4}{{{x}^{2}}}\] \[\Rightarrow \] \[{{x}^{4}}=2\] \[\Rightarrow \] \[x={{(2)}^{1/4}}\]You need to login to perform this action.
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