A) Rs. 1352
B) Rs. 1377
C) Rs. 1275
D) Rs. 1283
Correct Answer: A
Solution :
Let each instalment be\[=Rs.\,x\] \[\therefore \] \[x={{P}_{1}}{{\left( 1+\frac{4}{100} \right)}^{n}}\] \[\Rightarrow \] \[{{P}_{1}}=\left( \frac{25}{26} \right)x\] ?(i) Similarly, \[{{P}_{2}}={{\left( \frac{25}{26} \right)}^{2}}x\] ?(ii) \[\therefore \] \[\left( \frac{25}{26} \right)x+{{\left( \frac{25}{26} \right)}^{2}}x=2550\] \[\Rightarrow \] \[\left( \frac{25}{26} \right)x+\left( 1+\frac{25}{26} \right)=2550\] \[\Rightarrow \] \[x=\frac{2550\times 26\times 26}{25\times 51}=1352\] \[\therefore \] Each instalment be Rs. 1352.
You need to login to perform this action.
You will be redirected in
3 sec
