A) \[120\,\,\pi \,\,\text{c}{{\text{m}}^{\text{2}}}\]
B) \[60\,\,\pi \,\,\text{c}{{\text{m}}^{\text{2}}}\]
C) \[136\,\,\pi \,\,\text{c}{{\text{m}}^{\text{2}}}\]
D) \[68\,\,\pi \,\,\text{c}{{\text{m}}^{\text{2}}}\]
Correct Answer: C
Solution :
\[\because \] \[r=8\,cm\] and \[h=15\,cm\] \[\therefore \] \[l=\sqrt{{{r}^{2}}+{{h}^{2}}}\] \[=\sqrt{64+225}=\sqrt{289}=17\,cm\] \[\therefore \] Curved surface area of cone \[=\pi rl\] \[=\pi \times 8\times 17\] \[=136\pi \,\text{c}{{\text{m}}^{\text{2}}}\]
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