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SSC Sample Paper SSC CGL - Sample Paper-29

  • question_answer
    Two numbers have 16 as their HCF and 146 as their LCM. How many such pairs of numbers are there?

    A) Zero                 

    B) Only 1

    C) Only 2              

    D) Many

    Correct Answer: A

    Solution :

    HCF of two numbers\[=16\] and LCM of two numbers\[=146\] Let the first number, \[x=16a\] and the second number, \[y=16b\] We know that, HCF \[\times \] LCM = Product of two numbers \[\Rightarrow \]   \[16\times 146=x\times y\] \[\Rightarrow \]   \[16\times 146=16a\times 16b\] \[\Rightarrow \]   \[a\times b=\frac{146}{6}=9.125\] The number of such pairs is zero, since, \[a\times b\] is not a integer. 


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