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SSC Sample Paper SSC CGL - Sample Paper-29

  • question_answer
    What is the number which has to be added to each term of the ratio 49 : 68, so that it becomes 3: 4 ?

    A) 3                                 

    B) 5

    C) 8                     

    D) 9

    Correct Answer: C

    Solution :

    Let x number be added to 49 : 68, then it becomes 3 : 4 \[\therefore \]      \[\frac{49+x}{68+x}=\frac{3}{4}\] \[\Rightarrow \] \[196+4x=204+3x\] \[\Rightarrow \] \[x=8\]


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