A) Rs. 1500
B) Rs. 1200
C) Rs. 1100
D) Rs. 1000
Correct Answer: D
Solution :
We know that if the difference between CI and SI on a certain sum at r% per annum for 3 yr is Rs., x then sum is \[\frac{x(100)}{{{r}^{2}}(r+300)}\] Here, \[r=10%,\] \[x=Rs.\,31\] \[\therefore \] \[P=\frac{31{{(100)}^{3}}}{{{(10)}^{2}}(10+300)}\] \[=\frac{31\times 100\times 100\times 100}{100\times 310}\] \[=Rs.\,1000\]You need to login to perform this action.
You will be redirected in
3 sec