A) 59
B) 59.5
C) 60
D) 60.5
Correct Answer: C
Solution :
Given that, and \[{{n}_{1}}=8,\] \[{{x}_{1}}=51\] and \[{{n}_{2}}=9,\] \[{{x}_{2}}=68\] \[\therefore \] Average marks \[=\frac{{{n}_{1}}{{x}_{x}}+{{n}_{2}}{{x}_{2}}}{{{n}_{1}}+{{n}_{2}}}\] \[=\frac{8\times 51+9\times 68}{8+9}\] \[=\frac{1020}{17}=60\]You need to login to perform this action.
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