A) 12 L
B) 16 L
C) 18 L
D) 24 L
Correct Answer: C
Solution :
Let x L of several litres of acid drawn off initially. \[\therefore \] Remaining acid in the vessel \[=(54-x)L\] And quantity of water in the vessel \[=x\,L\] Now x L mixture is drawn off. \[\therefore \] Quantity of acid drawn off \[=\left( \frac{54-x}{54}\times x \right)L\] And quantity of water drawn off \[=\frac{{{x}^{2}}}{54}L\] Now the quantity of acid \[=\left[ 54-x-\left( \frac{54-x}{54} \right)x \right]L\] \[\therefore \] \[54-x-\frac{(54-x)}{54}x=24\] \[\Rightarrow \] \[{{x}^{2}}-108x+1620=0\] \[\Rightarrow \] \[x=90,\,\,18\] Since 90 > 54 there x = 90 is ruled out Hence, x = 18You need to login to perform this action.
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