A) 35 m East
B) 35 m North
C) 40 m East
D) 60 m East
Correct Answer: A
Solution :
The movements of Rohit are as shown in adjacent figure. \[\therefore \] Rohit's distance from starting point A \[=AE=(AD+DE)=(BC+DE)\] \[=\text{ (}20+15\text{) }m=35\text{ }m\] Also, E is to the East of A.You need to login to perform this action.
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