A) 1.4
B) 0.054
C) 0.8
D) 1.0
Correct Answer: A
Solution :
The given expression \[=\frac{{{(0.9)}^{3}}+{{(0.2)}^{3}}+{{(0.3)}^{2}}-3\times (0.9)\times (0.2)\times (0.3)}{{{(0.9)}^{2}}+{{(0.2)}^{2}}+{{(0.3)}^{2}}-(0.9)(0.2)-(0.2)(0.3)-(0.3)(0.9)}\] \[=\frac{\begin{align} & (0.9+0.2+0.3)[{{(0.9)}^{2}}+{{(0.2)}^{2}}+{{(0.3)}^{2}} \\ & \,\,\,\,\,\,\,\,\,-(0.9)(0.2)-(0.2)(0.3)-(0.3)(0.9)] \\ \end{align}}{\begin{align} & {{(0.9)}^{2}}+{{(0.2)}^{2}}+{{(0.3)}^{2}}-(0.9)(0.2) \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,-(0.2)(0.3)-(0.3)(0.9) \\ \end{align}}\] \[=(0.9+0.2+0.3)=1.4\]You need to login to perform this action.
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