A) \[20\sqrt{3}\,\,m\]
B) \[\frac{20}{\sqrt{3}}\,\,m\]
C) \[\frac{\sqrt{3}}{20}\,\,m\]
D) None of these
Correct Answer: B
Solution :
AB = height of tower. From \[\Delta ABC,\] \[\tan 30{}^\circ =\frac{AB}{BC}\] \[\Rightarrow \] \[\frac{1}{\sqrt{3}}=\frac{AB}{20}\] \[\Rightarrow \] \[AB=\frac{20}{\sqrt{3}}m\]You need to login to perform this action.
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