question_answer

The length of the diagonals of a rhombus are 16 cm and 12 cm. The side of the rhomobus is

A)  10 cm 

B)  9 cm

C)  8 cm                           

D)  7 cm

Correct Answer: A

Solution :

Let PQRS be a rhombus and \[PR=16\,cm\] and \[QS=12\,cm\] \[\therefore \]      \[PO=8\,cm\] And      \[QO=6\,cm\]             \[PQ=\sqrt{P{{O}^{2}}+O{{Q}^{2}}}\]             \[=\sqrt{{{8}^{2}}+{{6}^{2}}}\]             \[=\sqrt{64+36}\]             \[=\sqrt{100}=10\,cm\]