A) 80 days
B) 100 days
C) 60 days
D) 150 days
Correct Answer: C
Solution :
\[A+B-72\] days 1 work \[\therefore \] \[A+B\] in day \[\frac{1}{72}\] work Similarly. \[B+C\] in 1 day \[\frac{1}{120}\] work and \[A+C\] in 1 day \[\frac{1}{90}\] work \[\therefore \] \[2(A+B+C)\,\,1\] day \[\frac{1}{72}+\frac{1}{120}+\frac{1}{90}\] \[A+B+C\] in 1 day \[\frac{1}{2}\left( \frac{1}{72}+\frac{1}{120}+\frac{1}{90} \right)\] \[=\frac{1}{20}\left( \frac{10+6+8}{720} \right)\] \[=\frac{1}{2}\times \frac{24}{720}=\frac{1}{60}\] work \[A+B+C=\frac{1}{60}\] work = 1 days \[A+B+C=1\] work = 60 daysYou need to login to perform this action.
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