A) 40%
B) 32%
C) 22%
D) 8%
Correct Answer: D
Solution :
Since 18% of the students neither play football nor cricket. It means 82% of the students either play football or cricket or both. \[\therefore \] \[n(A\cup B)=n(A)+n(B)-n(A\cap B)\] \[\Rightarrow \] \[82=40+50-n(A\cap B)\] \[\Rightarrow \] \[n(A\cap B)\] \[=90-82=8\] \[\therefore \] 8% students play both games.You need to login to perform this action.
You will be redirected in
3 sec