A) 1
B) 2
C) 3
D) 4
Correct Answer: D
Solution :
Let \[4\frac{11}{15}\]\[=a\] and \[\frac{15}{71}=b\] \[\therefore \] Expression \[={{(a+b)}^{2}}-{{(a-b)}^{2}}\] \[=({{a}^{2}}+{{b}^{2}}+2ab)-({{a}^{2}}+{{b}^{2}}-2ab)=4ab\]\[=4\times 4\frac{11}{15}\times \frac{15}{71}\] \[=4\times \frac{71}{15}\times \frac{15}{71}=4\]You need to login to perform this action.
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