A) \[30{}^\circ \]
B) \[25{}^\circ \]
C) \[50{}^\circ \]
D) \[60{}^\circ \]
Correct Answer: B
Solution :
\[\angle AOB+130{}^\circ \] \[\Rightarrow \] \[\angle BOC=180{}^\circ -\angle AOB\] \[=50{}^\circ \] \[\angle BDC=\frac{1}{2}\angle BOC\] \[=\frac{1}{2}\times 50{}^\circ =25{}^\circ \]You need to login to perform this action.
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