A) \[1520\,\,c{{m}^{2}}\]
B) \[2420\,\,c{{m}^{2}}\]
C) \[2480\,\,c{{m}^{2}}\]
D) \[2520\,\,c{{m}^{2}}\]
Correct Answer: D
Solution :
Let the breadth of rectangle \[=x\,cm\] \[\therefore \] The length of rectangle \[=(x+23)\,cm\] \[\therefore \] \[2(x+23+x)=206\] \[\Rightarrow \] \[2x+23=103\] \[\Rightarrow \] \[2x=80\,\,\,\Rightarrow \,\,\,x=40\] \[\therefore \] Length of rectangle \[40+23=63\,\,c{{m}^{2}}\] and breadth of rectangle \[=40\,cm\] \[\therefore \] Area of rectangle \[=63\times 40=2520\,\,c{{m}^{2}}\]
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