A) 25
B) 26
C) 27
D) 28
Correct Answer: B
Solution :
Let the three consecutive natural Numbers are n, n +1 and n + 2. According to question, \[{{n}^{2}}+{{(n+1)}^{2}}+{{(n+2)}^{2}}=2030\] Or \[{{n}^{2}}++{{n}^{2}}+2n+1+{{n}^{2}}+4n+4=2030\] Or \[3{{n}^{2}}+6n-2025=0\] Or \[{{n}^{2}}+2n-675=0\] Or \[(n+27)(n-25)=0\] Or \[n=25\] \[[\because n\ne -\,27]\] \[\therefore \] Middle number \[=n+1=25+1=26\]You need to login to perform this action.
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