A) Rs. 40
B) Rs. 45
C) Rs. 50
D) Rs. 35
Correct Answer: A
Solution :
Let the CP of the article \[=Rs.\,x\] \[\therefore \] SP of the articled \[=Rs.\frac{9x}{10}\] New SP of the article \[=Rs.\frac{9x}{10}+9\] According to question, \[\frac{x\times 225}{200}=\frac{9x}{10}+9\] \[\Rightarrow \] \[x\left( \frac{225-180}{200} \right)=9\] \[\Rightarrow \] \[x=\frac{9\times 200}{45}\] \[\Rightarrow \] \[x=40\]You need to login to perform this action.
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