A) 30%
B) 50%
C) 20%
D) 25%
Correct Answer: B
Solution :
Suppose, \[P=100\] \[CI=225\] \[A=P{{\left( 1+\frac{r}{100} \right)}^{t}}\] Or \[225=100{{\left( 1+\frac{r}{100} \right)}^{2}}\] Or \[\frac{225}{100}={{\left[ 1+\frac{r}{100} \right]}^{2}}\] Or \[\left( \frac{1+r}{100} \right)=\frac{\sqrt{225}}{\sqrt{100}}\] Or \[1+\frac{r}{100}=\frac{15}{10}\] Or \[\frac{100+r}{100}=\frac{15}{10}\] Or \[100+r=150\] Or \[r=50%\]You need to login to perform this action.
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