question_answer

Sanjeev walks 10 m towards the South. Turning to the left, he walks 20 m and then moves to his right. After moving of 20 m, he turns to the right and walks 20 m. finally, he turns to the right and moves a distance of 10 m. How far and in which direction is he from the starting point?

A)  10 m, North                 

B)  20 m, South

C)  10 m, South                 

D)  20 m, North

Correct Answer: B

Solution :

The movements of sanjeev from A to F are as shown in figure given below Clearly, Sanjeev?s distance from starting point A             \[=AF=(AB+BF)\]             \[=AB+(BE-EF)=AB+(CD-EF)\]             \[=[10+(20-10)]m=(10+10)m=20\,m\] Also, F lies to the South of A. So, Sanjeev is 20 m to the South of his starting point.