A) 10 m, North
B) 20 m, South
C) 10 m, South
D) 20 m, North
Correct Answer: B
Solution :
The movements of sanjeev from A to F are as shown in figure given below Clearly, Sanjeev?s distance from starting point A \[=AF=(AB+BF)\] \[=AB+(BE-EF)=AB+(CD-EF)\] \[=[10+(20-10)]m=(10+10)m=20\,m\] Also, F lies to the South of A. So, Sanjeev is 20 m to the South of his starting point.You need to login to perform this action.
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