A) \[\pm \frac{1}{18}\]
B) \[\pm \frac{1}{8}\]
C) \[-\frac{1}{5}\]
D) \[\frac{1}{4}\]
Correct Answer: B
Solution :
\[x+\frac{1}{6}\sqrt{x}+{{a}^{2}}={{(\sqrt{x})}^{2}}+2\sqrt{x}\cdot \frac{1}{8}+{{(a)}^{2}}\] Clearly \[a=\frac{1}{8}\] Then, expression \[={{\left( \sqrt{x}+\frac{1}{8} \right)}^{2}}\]You need to login to perform this action.
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