A) \[\frac{22}{7}\times {{(15)}^{2}}c{{m}^{2}}\]
B) \[\frac{22}{7}\times {{\left( \frac{7}{2} \right)}^{2}}c{{m}^{2}}\]
C) \[\frac{22}{7}\times {{\frac{(15)}{2}}^{2}}c{{m}^{2}}\]
D) \[\frac{22}{7}\times {{\left( \frac{9}{2} \right)}^{2}}c{{m}^{2}}\]
Correct Answer: A
Solution :
Perimeter of square \[=20\,cm\] \[\therefore \] Side of square \[=30\,cm\] \[\therefore \] Radius of circle \[=15\,cm\] \[\therefore \] Area of circle \[=\frac{22}{7}\times {{(15)}^{2}}c{{m}^{2}}\]
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