A) 22 m
B) 20 m
C) 21 m
D) 55 m
Correct Answer: C
Solution :
Let the internal radius of the park be r and the external radius (with the path) be R. The difference between the internal and external Circumference is 132 m. \[\therefore \] \[2\pi R-2\pi r=132\] \[\Rightarrow \] \[2\pi (R-r)=132\] \[\Rightarrow \] \[R-r=\frac{132}{2\pi }\] \[=\frac{132\times 7}{2\times 22}=21\] Hence, the width of path \[=21\,m\]You need to login to perform this action.
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