A) \[10\frac{1}{2}\] days
B) 10 days
C) 9 days
D) 6 days
Correct Answer: B
Solution :
(A + B)'s 1 day's work \[=\frac{1}{12}\] (B + C)?s 1 day's work \[=\frac{1}{20}\] (C + A)s? 1 day's work \[=\frac{1}{15}\] On adding 2(A + B + C)?s 1 days?s work \[=\frac{1}{12}+\frac{1}{20}+\frac{1}{15}=\frac{1}{5}\] \[\therefore \] (A + B + C)?s 1 days?s work \[=\frac{1}{10}\] \[\therefore \] (A + B + C) together will complete the work in 10 days.
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