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SSC Sample Paper SSC CGL - Sample Paper-6

  • question_answer
    If \[x+\frac{1}{x}=6,\] then \[{{x}^{2}}+\frac{1}{{{x}^{2}}}=?\]

    A)  34       

    B)  32

    C)  36                               

    D)  38

    Correct Answer: A

    Solution :

    \[x+\frac{1}{x}=6\] \[\Rightarrow \]   \[{{\left( x+\frac{1}{x} \right)}^{2}}=36\] \[\Rightarrow \] \[{{x}^{2}}+\frac{1}{{{x}^{2}}}+2\times x\times \frac{1}{x}=36\] \[\Rightarrow \]   \[{{x}^{2}}+\frac{1}{{{x}^{2}}}=36-2=34\]            


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