A) 400 m
B) 150 m
C) 300 m
D) 250 m
Correct Answer: D
Solution :
Let O be the starting point. The car running at 36 km/h is moving along OB and that at 48 km/h moving along 36 km/h OA. Also let they reach at B and A after 15 s respectively. \[\therefore \] \[OA=48\times \frac{5}{18}\times 15=200\,m\] and \[OB=36\times \frac{5}{18}\times 15=150\,m\] \[\therefore \] Required distance = AB \[=\sqrt{{{(200)}^{2}}+{{(150)}^{2}}}\] \[=\sqrt{40000+22500}=\sqrt{62500}=250\,m\]You need to login to perform this action.
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